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Problems coming under other departments must be posted into the respective sections.
This section is a dedicated section for Maths only forum so please dont post problems under mechanical, electronics or any other in this category.



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neha
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#2
Wed Sep 23, 2009 10:15 pm
Post subject: Teaching to do a question about Quadratic equations.. Post
You know the area of the trapezium (76) and also that it consists of (4x + 3) * x = 4x^2 +3x

Therefore, 4x^2 + 3x = 76
=> 4x^2 + 3x - 76 = 0

Now you work this out:

Either use (b +/= root(b^2 - 4ac)) / 2a

or the quadratic solver at scicalculator.com (quadsolver.com)

The answer is 4 or -4.75 which is ignored as it can obviously not be a negative.

So x = 4. You can work out the rest of the question like that.

I would strongly recommend learning the formula as it is incredibly important.

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